Sandeep walks 60m to the east, then he turns left and walks for 50 m, then…

Concept: In a direction-and-distance problem, track each leg of the walk along a compass direction using the turn rule -- facing a direction, a left turn rotates you 90 degrees to that direction's left (East to North to West to South to East), and a right turn rotates 90 degrees the other way. The net displacement from the start is the vector sum of all the legs: equal-length movements in opposite directions (e.g., a northward leg and a southward leg of the same length) cancel completely, and what remains combines via the Pythagorean theorem -- which reduces to a plain sum when one component is zero.

1. Start facing East and walk 60 m East.

2. Turn left -- facing East, a left turn now faces North -- and walk 50 m North.

3. Turn right -- facing North, a right turn now faces East -- and walk 70 m East. The two eastward legs total 60 m + 70 m = 130 m.

4. Turn right again -- facing East, a right turn now faces South -- and walk 50 m South.

5. The 50 m North leg and the 50 m South leg are equal and opposite, so the vertical displacement cancels completely to 0 m.

6. Net displacement from the start = 130 m East + 0 m vertical = 130 m.

Cross-check: Taking the start as (0, 0) with East and North as the positive x- and y-axes, the four legs move the point to (60, 0), then (60, 50), then (130, 50), then (130, 0). The straight-line distance from (0,0) to (130,0) is 130 m, confirming the step-by-step sum.