Each of the questions given below consists of a statement and/or a question…
2025
Each of the questions given below consists of a statement and/or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is/are sufficient to answer the given question.
Read both the statements and Give answer
What is the probability that x3 – 8 = 0 when x is selected from a set of 8 integers?
Statement I. The smallest number in the set is -11
Statement II. The arithmetic mean of the set is 1/8.
- A.
if the data in Statement I alone is sufficient to answer the question, while the data in Statement II alone is not sufficient to answer the question.
- B.
if the data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question.
- C.
if the data in each Statement I and Statement II alone is sufficient to answer the question.
- D.
if the data even in both Statements I and II together are not sufficient to answer the question.
Show answer & explanation
Correct answer: D
In a Data Sufficiency question, a statement — or a combination of statements — is sufficient only when every scenario consistent with it produces the SAME unique answer; if two scenarios that both satisfy the given statement(s) disagree on the answer, the data is insufficient. Also, for a real number, an equation of the form x³ = k has exactly one real solution (its other two cube roots are complex).
Applying this here: x3 = 8 gives x = 2 as the only real solution, so the event “x3 – 8 = 0” is identical to the event “x = 2”. The required probability is (number of times the value 2 occurs among the 8 integers) ÷ 8, so a statement is sufficient here only if it fixes this count uniquely — not merely some summary property of the set as a whole.
Testing each statement against this requirement:
Statement I alone: only the minimum value (-11) is known. The sets {-11, -9, 1, 2, 3, 4, 5, 6} (contains 2) and {-11, -10, -9, -8, -7, -6, -5, -4} (does not contain 2) are both 8 distinct integers with minimum -11, so Statement I alone cannot fix whether — or how often — 2 appears.
Statement II alone: the arithmetic mean is 1/8, so the sum of the 8 integers is 1. The sets {-6, -2, -1, 0, 1, 2, 3, 4} (contains 2, sum = 1) and {-5, -4, -3, -1, 0, 1, 3, 10} (no 2, sum = 1) are both 8 distinct integers summing to 1, so Statement II alone cannot fix the count either.
Statements I and II together: even fixing both the minimum (-11) and the sum (1), the remaining numbers are still not uniquely determined — see the two combined-consistent sets below — so the count of 2's in the set remains undetermined.
This is confirmed by two sets of 8 distinct integers that both satisfy Statement I and Statement II but disagree on the answer:
{-11, -9, 1, 2, 3, 4, 5, 6} — minimum is -11, sum is 1, and 2 occurs once, giving probability 1/8.
{-11, -7, 0, 1, 3, 4, 5, 6} — minimum is -11, sum is 1, but 2 never occurs, giving probability 0.
Since both statements together still allow two different probabilities, the data — even combined — is not sufficient to answer the question. The correct choice is that the data in both Statements I and II together is not sufficient.