Choose the odd man out. Select any one.
2025
Choose the odd man out.
Select any one.
Answer: B. UWZ — Concept: In this letter-coding pattern, each three-letter word encodes two positional jumps along the alphabet - from the 1st letter to the 2nd, and from the…
- A.
BDI
- B.
UWZ
- C.
CEJ
- D.
MOT
Attempted by 5 students.
Show answer & explanation
Correct answer: B
Concept: In this letter-coding pattern, each three-letter word encodes two positional jumps along the alphabet - from the 1st letter to the 2nd, and from the 2nd letter to the 3rd (A=1, B=2, ... Z=26). Words sharing the same (jump1, jump2) pair belong to one group; the word whose jumps break that shared pattern is the odd one out.
Word | 1st -> 2nd letter (jump) | 2nd -> 3rd letter (jump) |
|---|---|---|
BDI | +2 (B to D) | +5 (D to I) |
CEJ | +2 (C to E) | +5 (E to J) |
MOT | +2 (M to O) | +5 (O to T) |
UWZ | +2 (U to W) | +3 (W to Z) |
Cross-check: BDI, CEJ, and MOT all share the identical (+2, +5) jump pattern - the first letter advances 2 positions to give the second letter, and the second letter advances 5 more positions to give the third. UWZ shares the same first jump (+2), but its second jump is only +3 (W to Z), which breaks the shared rule.
Result: Since UWZ is the only word whose jump pattern differs from the other three, UWZ is the odd one out.