Find the output of the following C++ code: int A[] = {20, 90, 70, 10}; int * P…

Correct Answer: 80

Reasoning:

• Interpretation: P is intended to be a pointer to int (int *P). P = A makes P point to the first element of the array A.

• A[2] starts as 70; the statement A[2] += 10 increases it to 80.

• P += 2 advances the pointer so it points to A[2].

• Dereferencing the pointer (*P) then yields 80, which is printed.

Note: The original code snippet appears to omit the pointer asterisk and the dereference in the print statement. For this result, the declarations and output should be int *P, A[] = {20, 90, 70, 10}; P = A; A[2] += 10; P += 2; cout << *P << endl;.