Train 1 leaves A at 8 am and reaches B at 2 pm. Train 2 leaves B at 10 am and…

Calculate travel times: Train 1 (8 am to 2 pm) = 6 hours. Train 2 (10 am to 6 pm) = 8 hours.

Set distance (D): Let the total distance be D. Speed of Train 1 = D/6; Speed of Train 2 = D/8.

Set up equation: Let 't' be the time in hours after 8 am.

Train 1 travels for 't' hours.

Train 2 travels for '(t - 2)' hours (starts 2 hours later).

Sum of distances = D: (D/6)t + (D/8)(t - 2) = D.

Solve for t: (t/6) + (t/8) - (2/8) = 1  =>  (4t + 3t) / 24 = 1 + 0.25  =>  7t / 24 = 1.25.

7t = 30  =>  t ≈ 4.29 hours.

Convert time: 4 hours + 0.29 * 60 minutes ≈ 4 hours and 17 minutes after 8 am, which is 12:17 pm.

Final Answer: Option 1 (12:17 pm)