Direction : Study the following information carefully and answer the questions…

Concept

In coded-inequality reasoning, first translate every symbol into a plain relational operator, then build one combined inequality chain. A conclusion is said to FOLLOW only if it is forced by the chain in EVERY consistent case; if even one valid arrangement breaks it, it does NOT follow. A ≤ link can never deliver a strict < outcome on its own, because equality remains possible.

Decoding the symbols

• @ = neither smaller nor equal → strictly greater (>)

• $ = not smaller → greater than or equal (≥)

• % = not greater → less than or equal (≤)

• * = neither smaller nor greater → equal (=)

• # = neither greater nor equal → strictly less (<)

Application — build the chain

1. A$B → A ≥ B

2. B%F → B ≤ F

3. F#D → F < D

4. Y@M → Y > M

5. M*F → M = F

6. Combined: A ≥ B ≤ F = M < D, with Y > M = F.

Testing each conclusion

• B < M : From B ≤ F and M = F we get B ≤ M. The relation allows B = M, so a strict B < M is not guaranteed — it does not follow.

• A ≤ Y : A is tied only to B (A ≥ B), while Y sits above F. No path links A and Y, so A could be larger than, equal to, or smaller than Y — it does not follow.

• Y > B : Y > M = F and B ≤ F, hence Y > F ≥ B gives Y > B in every case — this one is forced.

Cross-check

Take A = 10, B = 5, F = 5, M = 5, D = 8, Y = 9: all statements hold, yet B = M (so B < M fails) and A = 10 > 9 = Y (so A ≤ Y fails), while Y = 9 > 5 = B still holds. Only the Y > B conclusion survives every arrangement.

Result

Exactly one conclusion is definitely true: Y > B. Hence the response stating that only the third conclusion follows is correct.