Direction : Study the following information carefully and answer the questions…
2019
Direction : Study the following information carefully and answer the questions given below:
Eight persons are working in three different cities i.e. Delhi, Pune, Hyderabad. At least two persons are working in a city. There are four married couples of two generations. Number of males and females are equal in each city.
Note- Married couples are not working in same city. They have different designations i.e. GM, AGM, CEO, Manager, Assistant Manager, PO, Clerk, Sub staff (these are in decreasing order of seniority means GM is senior most and Sub staff is junior most person).
Only three persons are senior than the only son of B. B doesn’t work in Pune. E is sister in law of G who is junior most person. H is son in law of D, who is immediate senior of A. F is spouse of C and both are not working in Delhi. There are as many posts above father in law of A as below sibling of A. Only C and H are working in Hyderabad. Only PO and Sub staff are working in Delhi. Spouse of E is not working in Delhi. G is daughter in law of B who is spouse of D. F is senior than H and junior than C.
Which of the following combination is true?
- A.
B-PO-Delhi
- B.
C-CEO-Hyderabad
- C.
H-Clerk-Hyderabad
- D.
F-AGM-Delhi
- E.
None is true
Show answer & explanation
Correct answer: A
Concept
In a multi-variable arrangement puzzle, you do not guess — you convert each clue into a hard constraint and let the most restrictive clues fix the skeleton first. The governing idea here: a uniqueness clue (a fixed count, an "only" statement, or an immediate-senior relation) pins one variable exactly, and every later clue is then forced relative to that pin. The seniority ladder GM > AGM > CEO > Manager > Assistant Manager > PO > Clerk > Sub staff is the measuring stick; "posts above/below a person" simply counts ranks on this ladder.
Building the skeleton (apply each clue in order)
"Only C and H work in Hyderabad" fixes Hyderabad = {C, H}. "Only PO and Sub staff work in Delhi" means Delhi can hold at most those two posts, so Delhi has exactly 2 people; the remaining 4 go to Pune (sizes 2-2-4, each city with equal males and females).
"Only three persons are senior than the only son of B" puts the son of B at the 4th rank = Manager. "B is spouse of D", "G is daughter-in-law of B", and "H is son-in-law of D" give four couples: B-D (parents), and the children A and E marry G and H. Since E is the sister-in-law of G, E cannot be G's spouse, so the son of B is A and the daughter of B is E. Hence A = Manager, and A's spouse is G, E's spouse is H.
"D is immediate senior of A (Manager)" forces D = CEO. "G is the junior-most person" forces G = Sub staff.
B cannot be in Pune and is not in Hyderabad, so B is in Delhi; therefore B holds a Delhi post (PO or Sub staff). A is a Manager, so A is not in Delhi — A is in Pune. A and G are a couple (different cities), so G is in Delhi. Delhi = {B, G}, and since G = Sub staff, B = PO.
Pune is left with {A, D, E, F} (F is C's spouse and, being barred from Delhi and Hyderabad, sits in Pune). The remaining posts GM, AGM, Assistant Manager, Clerk go to C, E, F, H.
"F is senior than H and junior than C" and "as many posts above the father-in-law of A as below the sibling of A (E)" together leave exactly one assignment: C = GM, F = AGM, H = Assistant Manager, E = Clerk. (The father-in-law of A is F, with 1 post above him; E then has 1 post below her — both equal 1.)
Final arrangement
Person | Designation | City |
|---|---|---|
C | GM | Hyderabad |
D | CEO | Pune |
A | Manager | Pune |
F | AGM | Pune |
B | PO | Delhi |
E | Clerk | Pune |
H | Assistant Manager | Hyderabad |
G | Sub staff | Delhi |
Cross-check the combinations
B is the PO and works in Delhi — this combination is exactly true, so it is the answer.
C is the GM (not CEO), and H is the Assistant Manager (not Clerk), so both Hyderabad pairings fail.
F is the AGM but works in Pune, not Delhi, so that pairing fails. Since one combination does hold, "None is true" is ruled out.