For sum-of-products (SOP) simplification, each square of a K-map corresponds…
2017
For sum-of-products (SOP) simplification, each square of a K-map corresponds to which canonical term?
Answer: A. Min term — ConceptAn n-variable Karnaugh map contains 2n cells arranged in Gray-code order. Each cell corresponds to one unique input combination. In canonical SOP form,…
- A.
Min term
- B.
Max term
- C.
Average term
- D.
None of these
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Correct answer: A
Concept
An n-variable Karnaugh map contains 2n cells arranged in Gray-code order. Each cell corresponds to one unique input combination. In canonical SOP form, that combination is written as a product containing every variable once, complemented when its bit is 0 and uncomplemented when its bit is 1; this full product is a minterm.
Application
The stem explicitly asks about SOP simplification. Therefore the canonical term attached to a square is a minterm, so the accepted value is “Min term”.
Contrast
Min term: a canonical AND product that identifies one input combination in SOP form.
Max term: a canonical OR sum associated with one zero-output combination in POS form.
Average term: not a canonical Boolean-algebra term.
None of these: a set-level fallback, not a Boolean term.
Cross-check
For two variables A and B, the cell for A = 0 and B = 1 corresponds to A̅B, which contains both variables and is minterm m1. This confirms the SOP interpretation.
Result
Therefore, in SOP simplification each K-map square corresponds to a minterm; the accepted value is “Min term”.