An organization has a Class B network and wishes to form subnets for 64…

We are given a Class B network and need at least 64 subnets.

In Class B IP addressing:

Default subnet mask = 255.255.0.0 (/16)

We need to create ≥ 64 subnets

🔍 Step 1: Find subnet bits needed

Number of subnets formula:

2n ≥ 64

26 = 64

👉 So, we need 6 bits for subnetting

🔍 Step 2: New prefix length

Class B default = /16

Add 6 bits → /22

So new mask = /22

🔍 Step 3: Convert /22 to subnet mask

/22 means:

16 bits (first two octets) = 255.255

Next 6 bits in third octet:

Third octet binary:

11111100 = 252

So subnet mask =

👉 255.255.252.0

❌ Wait — check options carefully

We found correct mask = 255.255.252.0, which is actually in option B.

Let’s confirm:

/22 → 255.255.252.0 ✔️