What will be the output printed by the following C program? void main() { int…

Step 1: The variable x is initialized to 1, and y is initialized to 2. Step 2: The for loop runs for i = 0 to 4 (5 iterations). Step 3: Inside the loop, x << 1 performs a left shift on x, but the result is not assigned back to x. Therefore, x remains 1 throughout the loop. Step 4: In each iteration, y is updated as y = x + i. Since x is always 1, y becomes 1 + i. Step 5: After the loop, the final values are x = 1 and y = 1 + 4 = 5. Step 6: The printf statement prints the values of x and y, so the output is "1, 5".