For the following binary tree, inorder traversal yields the expression:

Solution: Inorder traversal (left, root, right)

1. Visit the left subtree of the root (the subtree with '+' as root).

2. In that subtree, visit its left child: a

3. Then visit the '+' node itself, appending + to the expression.

4. Now visit the right subtree of '+' which is the '*' node: visit its left child b, then '*' (*), then its right child d. This yields "b * d" for that subtree.

5. Combining the left subtree gives: a + b * d

6. Visit the root node - and append it.

7. Finally visit the right subtree (the '/' node): visit left child e, then '/' (/), then right child f. This yields "e / f".

Final inorder expression: a + b * d - e / f