Convert the infix expression to postfix expression ‘‘a+((b*c*(d/e^f)*g)*h)’’

Concept: To convert infix to postfix, scan left to right, send operands straight to the output, and use a stack for operators — pop and emit any stacked operator with equal or higher precedence before pushing the new one (associativity breaks ties: ^ is evaluated right-to-left, while *, /, and + are left-to-right). Precedence, highest to lowest, is ^, then * and /, then +. A '(' is pushed as a boundary marker; a ')' pops and emits back to the matching '(' and both parentheses are then discarded.

1. The expression is a + ((b * c * (d / e^f) * g) * h); precedence forces the innermost group (d / e^f) to convert first.

2. Inside that group, ^ binds tighter than /, so e^f becomes e f ^ before the division is applied, giving d / (e^f) → d e f ^ /.

3. Substituting back, b * c * (d/e^f) * g is a left-to-right chain of three '*' over the four values b, c, (d e f ^ /), and g: combining left to right gives b c *, then b c * d e f ^ / *, then b c * d e f ^ / * g *.

4. That whole product is then multiplied by h: (b c * d e f ^ / * g *) h * → b c * d e f ^ / * g * h *.

5. Finally, a is added: a + (…) → a b c * d e f ^ / * g * h * +.

Cross-check: the expression has 8 operands (a, b, c, d, e, f, g, h) and this postfix string carries exactly 7 binary operators (*, ^, /, *, *, *, +) — the required operand-minus-one count for a well-formed postfix string — and re-parenthesizing it by operator precedence reproduces the original infix expression exactly.

Result: a b c * d e f ^ / * g * h * +