What is the output of the following pseudocode ? int arr[] = {1, 2, 3, 4, 5}…

Array Initialization: An array arr is initialized with 5 elements:

• arr = 1

• arr = 2

• arr = 3

• arr = 4

• arr = 5

Pointer Arithmetic:

In pointer arithmetic, arr refers to the memory address of the first element (arr).

• arr + 2 moves the pointer forward by 2 elements, pointing to arr.

• Therefore, int *ptr = arr + 2; sets ptr to point to the element 3.

Dereferencing and Addition:

• *ptr dereferences the pointer, which gives the value at arr, which is 3.

• ptr + 1 points to the next consecutive element in memory, which is arr.

• *(ptr + 1) dereferences that next position, giving the value at arr, which is 4.

Final Print:

• print(*ptr + *(ptr + 1)) becomes print(3 + 4), which outputs 7.