The minimal expression of A + A'BA is

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The minimal expression of A + A'BA is

Answer: A. AConcept: In Boolean algebra, ANDing a variable with its own complement always gives 0 (Complement Law: X . X' = 0), and ORing any expression with 0 leaves it…

  1. A.

    A

  2. B.

    A + B

  3. C.

    AB

  4. D.

    B

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Show answer & explanation

Correct answer: A

Concept: In Boolean algebra, ANDing a variable with its own complement always gives 0 (Complement Law: X . X' = 0), and ORing any expression with 0 leaves it unchanged (Identity Law: X + 0 = X). The AND operation is commutative and associative, so the literals inside a product term can be regrouped in any order without changing its value.

Application:

  1. Start with the given expression: A + A'BA.

  2. Regroup the AND term using commutativity and associativity: A'BA = A . A' . B.

  3. Apply the Complement Law to the regrouped pair: A . A' = 0, so A'BA = 0 . B = 0.

  4. Substitute this back into the original expression: A + A'BA = A + 0.

  5. Apply the Identity Law: A + 0 = A.

  6. The expression reduces to the single literal A, which cannot be simplified further, so this is the minimal form.

Cross-check: Verifying with a truth table over every value of A and B confirms the reduction:

A

B

A'

A'BA

A + A'BA

0

0

1

0

0

0

1

1

0

0

1

0

0

0

1

1

1

0

0

1

Every row of A + A'BA matches the value of A exactly, confirming that the minimal expression is A.

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