Consider a subnet with 720 routers. If a three-level hierarchy is chosen, with…
2019
Consider a subnet with 720 routers. If a three-level hierarchy is chosen, with eight clusters, each containing 9 regions of 10 routers, then total number of entries in hierarchical table of each router is
- A.
25
- B.
27
- C.
53
- D.
72
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Correct answer: A
Solution:
Number of other clusters = total clusters - 1 = 8 - 1 = 7 (one aggregated entry for each other cluster).
Number of other regions in the same cluster = regions per cluster - 1 = 9 - 1 = 8 (aggregated entries for other regions within your cluster).
Number of routers in your own region = routers per region = 10 (individual entries for local routers).
Total entries = 7 + 8 + 10 = 25.
Therefore each router needs 25 entries in its hierarchical table.
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