In the standard Ethernet with transmission rate of 10Mbps, assume that the…

2022

In the standard Ethernet with transmission rate of 10Mbps, assume that the length of the medium is 2500 m and size of a frame is 512 bytes. The propagation speed of a signal in a cable is normally 2×108 m/s. Calculate Transmission delay and propagation delay.

  1. A.

    25.25𝜇s and 51.2𝜇s

  2. B.

    51.2𝜇S and 12.5𝜇s

  3. C.

    10.24𝜇s and 50.12𝜇s

  4. D.

    12.5𝜇s and 51.2𝜇s

Attempted by 22 students.

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Correct answer: B

Solution: Compute the transmission delay and propagation delay using the given values.

  • Transmission delay (t_tx) = frame size (bits) / bandwidth

    Frame size = 512 bytes = 512 × 8 = 4096 bits. Bandwidth = 10 Mbps = 10 × 10^6 bits/s. t_tx = 4096 / 10,000,000 = 0.0004096 s = 409.6 µs.

  • Propagation delay (t_prop) = distance / propagation speed

    Distance = 2500 m. Propagation speed = 2 × 10^8 m/s. t_prop = 2500 / (2 × 10^8) = 1.25 × 10^-5 s = 12.5 µs.

Answer: Transmission delay = 409.6 µs; Propagation delay = 12.5 µs.

Note: None of the provided options match these values. The key that gives a transmission delay of 51.2 µs assumes 512 bits instead of 512 bytes; that is the common mistake to avoid.

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