In the standard Ethernet with transmission rate of 10Mbps, assume that the…
2022
In the standard Ethernet with transmission rate of 10Mbps, assume that the length of the medium is 2500 m and size of a frame is 512 bytes. The propagation speed of a signal in a cable is normally 2×108 m/s. Calculate Transmission delay and propagation delay.
- A.
25.25𝜇s and 51.2𝜇s
- B.
51.2𝜇S and 12.5𝜇s
- C.
10.24𝜇s and 50.12𝜇s
- D.
12.5𝜇s and 51.2𝜇s
Attempted by 22 students.
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Correct answer: B
Solution: Compute the transmission delay and propagation delay using the given values.
Transmission delay (t_tx) = frame size (bits) / bandwidth
Frame size = 512 bytes = 512 × 8 = 4096 bits. Bandwidth = 10 Mbps = 10 × 10^6 bits/s. t_tx = 4096 / 10,000,000 = 0.0004096 s = 409.6 µs.
Propagation delay (t_prop) = distance / propagation speed
Distance = 2500 m. Propagation speed = 2 × 10^8 m/s. t_prop = 2500 / (2 × 10^8) = 1.25 × 10^-5 s = 12.5 µs.
Answer: Transmission delay = 409.6 µs; Propagation delay = 12.5 µs.
Note: None of the provided options match these values. The key that gives a transmission delay of 51.2 µs assumes 512 bits instead of 512 bytes; that is the common mistake to avoid.
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