A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per…
2025
A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minutes to deer’s 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?
- A.
600 m
- B.
700 m
- C.
800 m
- D.
1000 m
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Correct answer: C
Tiger takes 5 leaps/min and Deer takes 4 leaps/min
Thus, tiger runs at the speed of 5 x 8 = 40 m/min
and deer runs at the speed of 4 x 5 = 20 m/min
Tiger is 50 leaps behind, which is 50 x 8 = 400 m
Relative speed of tiger and deer is = 20 m/min
Thus, time taken by the tiger to catch the deer = 400/20 = 20 min
=> Distance travelled by the tiger before it catches the deer = 20 x 40 = 800 m