Practice Questions

Duration: 8 min

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This video is a tutorial on solving two quantitative aptitude problems related to profit and loss, presented by an instructor. The first problem, from an Accenture exam, involves finding the percentage loss (b%) when a man sells 12 units of a product at $10 with a loss of b% and then sells 12 units at $12 with a profit of b%. The instructor uses a 'short trick' method, setting up the equation 10/(100-b) = 12/(100+b) and solving for b, which results in b = 11%. The second problem, from an L&T Infotech exam, asks for the selling price of the second cycle to achieve an overall 15% profit, given that the first cycle was sold at a 20% loss. The instructor uses a 'short trick' method, calculating the total cost price (Rs. 2400), the desired total selling price (Rs. 2760), and the selling price of the first cycle (Rs. 960), leading to the final answer of Rs. 1800. The video uses a green chalkboard for calculations and includes on-screen text for the questions and options.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a title card showing a 3D figure on a balance scale with 'PROFIT' and 'LOSS' on either side, setting the theme of the lesson. It then transitions to a screen displaying the first problem (Q1) from an Accenture exam. The problem states: 'Mr. Ajay Devgan sold 12 Vimal Paan Masala at 10 dollars had a loss of b% and again sold 12 Vimal at 12 dollars had a profit of b%. Find the value of b?'. The options are a) 10%, b) 9.09%, c) 8%, d) 11%. The instructor, Yash Jain Sir, introduces the problem and the 'short trick' method to solve it, which involves equating the cost price (CP) from both transactions. The on-screen text also includes a meme with the text 'Kya kha rahi ho?' and 'Chocolate' and 'Vimal khaya karo'. The instructor begins to write the first part of the equation on the green board: 'Rs. = Rs. / (100-b) = 12 / (100+b)'. The video also shows a banner at the bottom with social media links for the 'Knowledge Gate Educator'.

  2. 2:00 – 5:00 02:00-05:00

    The instructor continues to solve the first problem on the green chalkboard. He writes the equation 10/(100-b) = 12/(100+b) and proceeds to cross-multiply, writing '10(100+b) = 12(100-b)'. He then expands the equation to '1000 + 10b = 1200 - 12b'. The instructor combines like terms, writing '10b + 12b = 1200 - 1000', which simplifies to '22b = 200'. He then divides both sides by 22, writing 'b = 200/22', which simplifies to 'b = 100/11'. He concludes that b = 9.09%, which corresponds to option (b). The on-screen text 'Short Trick' is visible, and the instructor explains that this method is faster than the traditional approach. The video also shows a banner at the bottom with social media links for the 'Knowledge Gate Educator'.

  3. 5:00 – 7:55 05:00-07:55

    The video transitions to the second problem (Q2) from an L&T Infotech exam. The problem states: 'A man buys two cycles for Rs. 1200 each, he sells first cycle at a loss of 20%, if he desires to get a profit of 15% on whole, for how much he should sell his 2nd cycle?'. The options are a) Rs. 2000, b) Rs. 1500, c) Rs. 1800, d) Rs. 1700. The instructor introduces the 'short trick' method. He calculates the total cost price (CP) as 1200 + 1200 = Rs. 2400. He then calculates the desired total selling price (SP) for a 15% profit as 2400 * 1.15 = Rs. 2760. He calculates the selling price of the first cycle at a 20% loss as 1200 * 0.8 = Rs. 960. He then subtracts the first cycle's SP from the total desired SP: 2760 - 960 = Rs. 1800. The instructor concludes that the answer is Rs. 1800, which is option (c). The video ends with a 'THANKS FOR WATCHING' screen.

The video presents a structured tutorial on solving profit and loss problems using efficient 'short trick' methods. It begins with a problem where the same percentage loss and profit are applied to different selling prices, requiring the student to find the percentage value by equating the cost price. The solution involves setting up a proportion and solving a linear equation. The second problem is a classic two-item transaction where the goal is to find the selling price of the second item to achieve a desired overall profit, given the loss on the first. The instructor demonstrates a methodical approach by calculating the total cost, the total desired revenue, and then the required revenue from the second item. The core learning objective is to apply these shortcuts to solve complex problems quickly, which is essential for competitive exams.