Four friends namely Rahul, Ravi, Rajesh and Rohan contested for a dairy milk…
2026
Four friends namely Rahul, Ravi, Rajesh and Rohan contested for a dairy milk chocolate. To decide which friend will get the chocolate they decided to throw two dice. Every friend was asked to choose a number and if the sum of the numbers on two dice equals that number, the concerned person will get the chocolate. Rahul's choice was7, Ravi's choice was 9, Rajesh's choice was 10 and Rohan's choice was 11. Who has the maximum probability of winning the amount.
- A.
Ravi
- B.
Rahul
- C.
Rajesh
- D.
Rohan
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Correct answer: B
To decide who is most likely to win, we must compare how many outcomes of throwing two fair dice give each chosen sum.
Rahul chooses the sum 7. The outcomes that give 7 are (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1). So there are 6 favorable outcomes for a sum of 7.
Ravi chooses the sum 9. The outcomes that give 9 are (3,6), (4,5), (5,4) and (6,3). So there are 4 favorable outcomes for a sum of 9.
Rajesh chooses the sum 10. The outcomes that give 10 are (4,6), (5,5) and (6,4). So there are 3 favorable outcomes for a sum of 10.
Rohan chooses the sum 11. The outcomes that give 11 are (5,6) and (6,5). So there are 2 favorable outcomes for a sum of 11.
When two dice are thrown, there are 36 equally likely outcomes in total. The more favorable outcomes a sum has, the higher its probability. Since the sum 7 has 6 favorable outcomes, which is more than for 9, 10 or 11, Rahul, who chose 7, has the maximum probability of winning the chocolate.