A man can hit a target once in 3 shots. If he fires 3 shots in succession,…

Let the probability of hitting the target with a single shot be 1/3.

Then the probability of missing the target with a single shot is 1 - 1/3 = 2/3.

Assuming the three shots are independent:

• Probability of missing all three shots = (2/3)^3 = 8/27.

• Probability of hitting the target at least once in three shots = 1 - 8/27 = 19/27.

So, the probability that he hits the target is 19/27.