In a vessel , there are 20 litres of alcohol . An operation is defined as…

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In a vessel , there are 20 litres of alcohol . An operation is defined as taking out five litres of what is present in the vessel and adding 5 litres of pure water to it . What is the ratio of alcohol to water after two operatons?

  1. A.

    5:7

  2. B.

    2:3

  3. C.

    9:7

  4. D.

    3/7

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Correct answer: C

Answer: 9 : 7

Key idea: Each operation removes 5 litres out of 20, i.e. removes 1/4 of the mixture. So the fraction of alcohol remaining after one operation is 1 - 1/4 = 3/4. Repeating the operation multiplies the alcohol amount by 3/4 again.

  1. Alcohol after two operations = 20 * (3/4)^2 = 20 * 9/16 = 45/4 litres.

  2. Water after two operations = total - alcohol = 20 - 45/4 = 35/4 litres.

  3. Ratio alcohol : water = (45/4) : (35/4) = 45 : 35 = 9 : 7.

Alternate sequential method:

  • After 1st operation: remove 5 L alcohol → alcohol = 20 - 5 = 15 L, water = 5 L.

  • After 2nd operation: remove (5/20)*15 = 75/20 = 15*1/4 = 15/4 L alcohol, so remaining alcohol = 15 - 15/4 = 45/4 L; water = 20 - 45/4 = 35/4 L.

Hence the required ratio is 9 : 7.

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