A man has some hens and some cows. If the number of heads is 50 and number of…

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A man has some hens and some cows. If the number of heads is 50 and number of feet is 142. The number of cows is:

  1. A.

    22

  2. B.

    44

  3. C.

    21

  4. D.

    116

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Correct answer: C

Solution:

Let h = number of hens and c = number of cows.

  1. Heads: h + c = 50.

  2. Feet: 2h + 4c = 142.

  3. Substitute h = 50 - c into the feet equation: 2(50 - c) + 4c = 142.

  4. Simplify: 100 - 2c + 4c = 142 ⇒ 2c = 42 ⇒ c = 21.

Therefore, number of cows = 21 and number of hens = 29.

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