If x = 2³² − 1, then what is the sum of the factors of x that lie between 1…

2026

If x = 2³² − 1, then what is the sum of the factors of x that lie between 1 and 100?

Hint: 2^(2ⁿ) + 1 is prime for n = 1, 2, 3, 4.

  1. A.

    314

  2. B.

    176

  3. C.

    143

  4. D.

    431

Attempted by 233 students.

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Correct answer: B

We need to find the factors of x = 2³² − 1 that lie between 1 and 100.

Use the factorization:
2³² − 1 = (2¹ + 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

So,
2³² − 1 = 3 × 5 × 17 × 257 × 65537.

Only the prime factors 3, 5, and 17 can form factors below 100. The factors between 1 and 100 are:
3, 5, 15, 17, 51, 85

Sum = 3 + 5 + 15 + 17 + 51 + 85 = 176.

Correct Answer: Option B (176).

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