Four times the first of three consecutive odd integers is 6 more than twice…
2026
Four times the first of three consecutive odd integers is 6 more than twice the third. Find the third integer. ___
- A.
7
- B.
9
- C.
11
- D.
10
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Correct answer: C
Let the first odd integer be n. The three consecutive odd integers are n, n + 2, and n + 4.
Equation: 4n = 2(n + 4) + 6
Solve: 4n = 2n + 8 + 6 = 2n + 14, so 2n = 14 and n = 7.
Third integer: n + 4 = 7 + 4 = 11.
Correct answer: 11