If 5+3+2=151022, 9+2+4=183652, then 7+2+5=?

In this kind of number-coding puzzle, each expression 'a+b+c' is coded as three two-digit blocks placed side by side: the product of the first and second numbers (a×b), the product of the first and third numbers (a×c), and the sum of those two products reduced by the middle number (a×b + a×c − b).

1. Check the first clue, 5+3+2 (a=5, b=3, c=2): a×b = 5×3 = 15; a×c = 5×2 = 10; a×b + a×c − b = 15 + 10 − 3 = 22. Placing these blocks side by side, 15-10-22, gives 151022, matching the clue.

2. Check the second clue, 9+2+4 (a=9, b=2, c=4): a×b = 9×2 = 18; a×c = 9×4 = 36; a×b + a×c − b = 18 + 36 − 2 = 52. Placing these blocks side by side, 18-36-52, gives 183652, matching the clue and confirming the rule holds for both examples.

3. Apply the same rule to 7+2+5 (a=7, b=2, c=5): a×b = 7×2 = 14; a×c = 7×5 = 35; a×b + a×c − b = 14 + 35 − 2 = 47.

4. Placing the three blocks side by side in order — 14, 35, 47 — gives 143547.

As an independent check, recompute the adjustment step in a different order — first add the two products (14 + 35 = 49), then subtract the middle number (49 − 2 = 47) — the result still comes out to 47, and the same three-block structure that correctly reproduced both given clues reproduces this one too.

So 7+2+5 is coded as 143547.