The famous church in the city has a big clock tower and is said to be over 200…

Concept: When a clock runs slow, it loses a fixed number of minutes for every 60 minutes of true (correct) time. So the time shown by the faulty clock and the true elapsed time are always in a fixed ratio — the same ratio scales any faulty-clock reading to the true elapsed time, and vice versa.

Application:

1. Find the duration shown by the faulty clock. From Monday 10:00 AM to Thursday 1:00 PM is 3 full days (72 hours) plus 3 more hours, i.e. 75 hours on the faulty clock.

2. The clock loses 6 minutes every hour, so for every 60 minutes of true time it advances only 54 minutes (60 minus 6 equals 54).

3. So 54 minutes on the faulty clock corresponds to 60 minutes of true time — that is, 1 hour on the faulty clock corresponds to 60/54, i.e. 10/9, hours of true time.

4. True elapsed time = 75 times 10/9 = 83 hours 20 minutes.

5. 83 hours 20 minutes is 3 days (72 hours) plus 11 hours 20 minutes. Adding this to Monday 10:00 AM gives Thursday 10:00 AM plus 11 hours 20 minutes, which is Thursday 9:20 PM.

Cross-check: In 83 hours 20 minutes of true time, the faulty clock should show 83 hours 20 minutes times 54/60, which is 75 hours — exactly the duration used above, confirming the result.

So the actual time is 9:20 PM Thursday.