A play school has chocolates that can supply 60 students for 40 days. For the…
2025
A play school has chocolates that can supply 60 students for 40 days. For the first twenty days, only 30 students were present. How many more students can be accommodated in the group so that the entire stock of chocolates gets consumed within the scheduled 40 days? Assume each student takes the same number of chocolates per day.
- A.
75
- B.
60
- C.
90
- D.
45
Show answer & explanation
Correct answer: B
This is a resource-consumption (work-equivalence) problem: a fixed total quantity of a resource lasts a certain number of people for a certain number of days, and (number of people) x (number of days) always equals that same fixed total, provided each person consumes at the same steady rate per day.
The play school's chocolates are enough for 60 students for 40 days, so the total stock equals 60 x 40 = 2400 student-days worth of chocolate.
Only 30 students were actually present for the first twenty days, so the chocolate actually used in that period = 30 x 20 = 600 student-days worth.
Chocolate left after day 20 = 2400 - 600 = 1800 student-days worth.
The stock must still be fully used up within the originally scheduled 40 days, so it has to last exactly the 40 - 20 = 20 days that remain.
Let x be the number of extra students who join, making the new strength (30 + x). To use up the remaining 1800 units in exactly 20 days: (30 + x) x 20 = 1800.
Divide both sides by 20: 30 + x = 90, so x = 90 - 30 = 60.
Checking the whole timeline independently: the first 20 days use 30 x 20 = 600 units, and the remaining 20 days with 90 students use 90 x 20 = 1800 units; 600 + 1800 = 2400, exactly the total stock, confirming the count is consistent from start to finish.
So 60 more students can be accommodated.
