Two cars start from A and B and travel towards each other at speeds of 59 kmph…

When two bodies move towards each other from opposite ends of a straight path, the gap between them shrinks at a rate equal to the SUM of their speeds (relative speed = v1 + v2). If they travel for the same duration but their individual distances differ, that difference equals the DIFFERENCE of their speeds multiplied by the common travel time.

1. Let the two cars meet after t hours. Car 1 travels at 59 kmph and Car 2 travels at 60 kmph, so by the meeting point Car 1 covers 59t km and Car 2 covers 60t km.

2. The second car has travelled 120 km more than the first, so 60t − 59t = 120.

3. The speed difference is 60 − 59 = 1 kmph, so this simplifies to t = 120 hours.

4. The distance between A and B equals the sum of the two distances covered: 59t + 60t = 119t.

5. Substituting t = 120 hours: 119 × 120 = 14280 km.

Cross-check: in 120 hours, Car 1 covers 59 × 120 = 7080 km and Car 2 covers 60 × 120 = 7200 km. Their difference, 7200 − 7080 = 120 km, matches the given condition, and their sum, 7080 + 7200 = 14280 km, confirms the total distance.