The number of natural numbers n such that (n + 1)2/(n + 7) is an integer is:

2026

The number of natural numbers n such that (n + 1)2/(n + 7) is an integer is:

  1. A.

    4

  2. B.

    5

  3. C.

    6

  4. D.

    None of these

Attempted by 11 students.

Show answer & explanation

Correct answer: A

Concept

To count integer values of a rational expression like (n + 1)

2/(n + 7), rewrite it by polynomial division as Quotient + Remainder/(n + 7). The expression is an integer exactly for those natural numbers n for which (n + 7) divides that fixed remainder -- i.e., for which (n + 7) is a divisor of the remainder.

Application

  1. Expand (n + 1)2 = n2 + 2n + 1.

  2. Divide by (n + 7): n2 + 2n + 1 = (n + 7)(n - 5) + 36, so the expression equals (n - 5) + 36/(n + 7).

  3. For the expression to be an integer, (n + 7) must be a divisor of 36.

  4. The positive divisors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36.

  5. Since n is a natural number (n >= 1), (n + 7) >= 8, so only divisors of 36 that are at least 8 qualify: 9, 12, 18, 36.

  6. Each qualifying divisor gives one valid n: n+7=9 -> n=2; n+7=12 -> n=5; n+7=18 -> n=11; n+7=36 -> n=29.

  7. That is exactly 4 natural numbers.

Cross-check

n = 2: (3)2/9 = 9/9 = 1, an integer. n = 29: (30)2/36 = 900/36 = 25, an integer. Both confirm the count.

Result

There are 4 such natural numbers.

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