Directions : There are three quantities provided in the questions. You have to…
2018
Directions : There are three quantities provided in the questions. You have to find out the values of the quantities and compare them according to the given codes as follows
@ → >
& → <
* → ≥
$ → ≤
# → = (or relationship can’t be established)
Example :
Quantity I: 3² + 5³
Quantity II: 5² × 2²
Quantity III: 100
(a) @, $
(b) , #
(c) $, #
(d) &,
(e) @, #
Quantity I > Quantity II = Quantity III
So, answer is (e)
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Quantity I – Coaching teacher asked a question to three students A, B & C and probability of question not being answered by three students is 0.5, 0.4, 0.7 respectively. Find the probability that at most two students will solve the question.
Quantity II – A bag contains 5 green balls & 7 red balls, if three balls drawn at random from bag, then find probability of getting at least 1 green ball.
Quantity III – Arun speaks the truth 4 out of 5 times, and Bhavya speaks the truth 6 out of 7 times. What is the probability that they will contradict each other in stating the same fact?
- A.
(@, &)
- B.
(#, @)
- C.
(@, @)
- D.
(&, a)
- E.
(*, #)
Attempted by 1 students.
Show answer & explanation
Correct answer: C
Quantity I: probability at most two students solve = 1 - probability all three solve = 1 - (0.5 x 0.6 x 0.3) = 0.91.
Quantity II: probability of at least one green ball = 1 - C(7,3)/C(12,3) = 1 - 35/220 = 185/220.
Quantity III: probability of contradiction = (4/5 x 1/7) + (1/5 x 6/7) = 10/35. Hence Quantity I > Quantity II > Quantity III, so the relation is (@, @).