In triangles ABC and DEF; ∠B = 90°, BC = 8 cm, ∠A = 40°, DE = 8 cm, ∠F = 40°…
2024
In triangles ABC and DEF; ∠B = 90°, BC = 8 cm, ∠A = 40°, DE = 8 cm, ∠F = 40° and ∠E = 90°. Then, which of the following statements is true?
- A.
ΔABC ≅ ΔDEF, by RHS
- B.
ΔABC ≅ ΔFED, by RHS
- C.
ΔABC ≅ ΔDFE, by AAS
- D.
ΔABC ≅ ΔFED, by AAS
Show answer & explanation
Correct answer: D
Concept: Two angles of a triangle fix the third, since a triangle's angles sum to 180°. Two equal angles together with one equal side then fix a unique congruence rule between two triangles: ASA when the equal side lies between the two given angles (the included side), AAS when it lies opposite one of them (a non-included side), and RHS when, for right triangles specifically, the hypotenuse and one leg are equal.
In ΔABC, ∠C = 180° − (∠A + ∠B) = 180° − (40° + 90°) = 50°.
In ΔDEF, ∠D = 180° − (∠F + ∠E) = 180° − (40° + 90°) = 50°.
Matching equal angles between the two triangles: ∠A = ∠F = 40°, ∠B = ∠E = 90°, ∠C = ∠D = 50° — so the vertex correspondence is A↔F, B↔E, C↔D.
The equal side (BC = DE = 8 cm) joins vertices B and C in the first triangle and D and E in the second, so it lies opposite vertex A in the first triangle and opposite vertex F in the second — a side that is NOT included between the two given angles.
Two equal angles with a non-included equal side is the AAS pattern, not ASA (the included side would be AB and FE, which were not given).
Writing the congruence in the matched vertex order (A↔F, B↔E, C↔D): ΔABC ≅ ΔFED, by AAS.
Cross-check: RHS is ruled out because the equal side (BC, DE) is a leg next to the right angle in each triangle, not the hypotenuse (AC and FD, which are not given); and reversing the correspondence to ΔDFE would require A to pair with D, which contradicts the angle match above — so the AAS correspondence ΔABC ≅ ΔFED is the one that holds.