If the selling price of Rs 235 results in a discount of 6% on the marked price…

Concept — A discount is always reckoned on the marked price, never on the price that is actually charged. If MP is the marked price and d is the rate of discount, the selling price is SP = MP × (1 − d). Rearranging gives MP = SP ÷ (1 − d). So once the marked price has been recovered from one discount rate, the price under any other rate d′ on the same article follows as SP′ = MP × (1 − d′).

Application — apply that relation to the figures given here.

1. The quoted price of Rs 235 is what remains after a 6% discount, so 235 = MP × (1 − 0.06) = 0.94 × MP.

2. Recover the marked price: MP = 235 ÷ 0.94 = Rs 250.

3. Apply the required 15% discount to that same marked price: SP′ = 250 × (1 − 0.15) = 250 × 0.85.

4. SP′ = Rs 212.50, so the item should be sold at Rs 212.50.

Cross-check — 15% of 250 is 37.50, and 250 − 37.50 = 212.50. The same figure comes out in a single step by scaling the two discount factors against each other: 235 × (0.85 ÷ 0.94) = 212.50.

Common slip — reducing Rs 235 itself by 15% gives Rs 199.75. That treats an already-discounted price as the base, whereas both discount rates in this problem are measured from the same marked price.