A man borrows ₹1,024 at 50% per annum, compounded half-yearly, for 2 years.…
2024
A man borrows ₹1,024 at 50% per annum, compounded half-yearly, for 2 years. What amount must he repay at the end of the loan period?
Answer: B. ₹2,500 — ConceptFor compound interest, the amount after t years is A = P(1 + r/m)mt, where P is the principal, r is the annual rate in decimal form, and m is the…
- A.
₹2,048
- B.
₹2,500
- C.
₹5,344
- D.
₹5,184
Attempted by 5 students.
Show answer & explanation
Correct answer: B
Concept
For compound interest, the amount after t years is A = P(1 + r/m)mt, where P is the principal, r is the annual rate in decimal form, and m is the number of compounding periods per year.
With half-yearly compounding, m = 2, so the annual rate is divided by 2 and the number of years is multiplied by 2.
Application
Convert the annual rate: r = 50/100 = 0.50. Therefore, the rate per half-year is 0.50/2 = 0.25.
Count the compounding periods: n = 2 × 2 = 4 half-years.
Substitute in the formula: A = 1,024(1 + 0.25)4 = 1,024(5/4)4.
Evaluate: A = 1,024 × 625/256 = 4 × 625 = ₹2,500.
Cross-check
The growth factor for one year is (5/4)2 = 25/16. Over two years it is (25/16)2 = 625/256, and ₹1,024 × 625/256 = ₹2,500, confirming the calculation.
Result
The amount to be repaid at the end of 2 years is ₹2,500.