Two students A and B appeared in an examination in which A scored 12% more…

2017

Two students A and B appeared in an examination in which A scored 12% more than B. B scored approximately what percent less than A?

Answer: D. 10.7%Solution: To find how much percent B is less than A, measure the difference relative to A. Step 1: Choose a convenient value for B, for example B = 100. Step…

  1. A.

    20%

  2. B.

    16.67%

  3. C.

    12%

  4. D.

    10.7%

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Correct answer: D

Solution: To find how much percent B is less than A, measure the difference relative to A.

  • Step 1: Choose a convenient value for B, for example B = 100.

  • Step 2: Since A scored 12% more than B, A = 100 + 12 = 112.

  • Step 3: Percent by which B is less than A = (A − B)/A × 100 = (112 − 100)/112 × 100 = 12/112 × 100 ≈ 10.714%.

Answer: Approximately 10.7%.

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