What is the difference between the number of male participants and the number…

Concept

When a group of N members is split between two categories in the ratio m : f, one share (one "part") equals N/(m + f). The two categories differ by (m − f) such parts, so the gap between them is N × (m − f)/(m + f). Counts taken from separate groups simply add up, so the overall gap for an event is the sum of the group-wise gaps — the ratios themselves must never be added.

Application

Read only the E2 columns of the table and apply gap = N × (m − f)/(m + f) to each country:

Working each row out in full:

1. India: one part = 500/25 = 20, so males = 17 × 20 = 340 and females = 8 × 20 = 160; gap = 180.

2. US: one part = 1440/12 = 120, so males = 7 × 120 = 840 and females = 5 × 120 = 600; gap = 240.

3. China: one part = 1160/20 = 58, so males = 13 × 58 = 754 and females = 7 × 58 = 406; gap = 348.

4. Russia: one part = 1320/11 = 120, so males = 7 × 120 = 840 and females = 4 × 120 = 480; gap = 360.

5. England: one part = 840/14 = 60, so males = 9 × 60 = 540 and females = 5 × 60 = 300; gap = 240.

6. Germany: one part = 728/4 = 182, so males = 3 × 182 = 546 and females = 1 × 182 = 182; gap = 364.

7. Total gap = 180 + 240 + 348 + 360 + 240 + 364 = 1732.

Cross-check

Add the six E2 headcounts: 500 + 1440 + 1160 + 1320 + 840 + 728 = 5988. Since males + females = 5988 and males − females = 1732, males = (5988 + 1732)/2 = 3860 and females = (5988 − 1732)/2 = 2128. The country-wise male counts add to 340 + 840 + 754 + 840 + 540 + 546 = 3860 and the female counts to 160 + 600 + 406 + 480 + 300 + 182 = 2128, which matches.

So across all six countries the male participants in E2 exceed the female participants by 1732.