What is the average annual growth rate of CO2 emissions in power sector ?

2014

What is the average annual growth rate of CO2 emissions in power sector ?

Answer: A. ~12.57%ConceptThe average annual growth rate of a quantity over several years is the arithmetic mean of its year-on-year percentage changes. For two consecutive…

  1. A.

    ~12.57%

  2. B.

    ~16.87%

  3. C.

    ~30.81%

  4. D.

    ~50.25%

Show answer & explanation

Correct answer: A

Concept

The average annual growth rate of a quantity over several years is the arithmetic mean of its year-on-year percentage changes. For two consecutive years, the growth rate of the later year is given by:

(Vnext − Vprev) ÷ Vprev × 100

The denominator is always the earlier year’s value, and a list of n + 1 data years contains exactly n one-year intervals. So the average annual growth rate = (sum of the n annual rates) ÷ n — divided by the number of intervals, not by the number of years listed.

Application

Read only the Power column of the table: 2005 = 500, 2006 = 600, 2007 = 650, 2008 = 700 and 2009 = 800 (million metric tons). Five data years give four consecutive one-year intervals.

Interval

Calculation

Annual growth rate

2005 → 2006

(600 − 500) ÷ 500 × 100

20.00%

2006 → 2007

(650 − 600) ÷ 600 × 100

8.33%

2007 → 2008

(700 − 650) ÷ 650 × 100

7.69%

2008 → 2009

(800 − 700) ÷ 700 × 100

14.29%

  1. Add the four annual rates: 20.00 + 8.33 + 7.69 + 14.29 = 50.31%.

  2. Divide that total by the number of intervals, which is 4: 50.31 ÷ 4 = 12.58%.

  3. To the precision offered by the choices, the average annual growth rate of the power sector is about 12.57%.

Cross-check

A compound (geometric) check agrees. The compound annual growth rate over the same span is:

(800 ÷ 500)1/4 − 1 = 1.60.25 − 1 ≈ 12.47%

That compound figure of about 12.47% per year sits right beside the arithmetic mean of 12.58% and confirms the scale of the result.

Two slips change the size of the answer sharply: leaving the total of 50.31% un-averaged, or dividing it by 3 instead of by the 4 actual one-year intervals. Both give figures far larger than the correct 12.57%.

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