Two numbers are such that their product is equal to 21 and the sum of their…
2023
Two numbers are such that their product is equal to 21 and the sum of their squares is 58. Find the difference between the two numbers.
Answer: A. 4 — ConceptFor any two real numbers x and y, the identity (x − y)2 = x2 + y2 − 2xy connects their difference with the sum of their squares and their product.…
- A.
4
- B.
5
- C.
6
- D.
8
Show answer & explanation
Correct answer: A
Concept
For any two real numbers x and y, the identity (x − y)2 = x2 + y2 − 2xy connects their difference with the sum of their squares and their product.
Because a difference is taken as a magnitude here, the required value is |x − y| = √(x2 + y2 − 2xy).
Application
Let the two numbers be x and y. The given data are xy = 21 and x2 + y2 = 58.
Substitute these values: (x − y)2 = 58 − 2 × 21.
Simplify: (x − y)2 = 58 − 42 = 16.
Take the non-negative square root: |x − y| = √16 = 4.
Cross-check
The integer pair 3 and 7 has product 21 and square sum 32 + 72 = 9 + 49 = 58; its difference is 7 − 3 = 4.
Therefore, the difference between the two numbers is 4.