Based on the alphabetical order, three of the following four are alike in a…
2026
Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster)
Answer: B. KNT — Concept — In an alphabet-based classification, every letter is replaced by its position in the English alphabet (A = 1, B = 2, ... , Z = 26). The ordered…
- A.
NQV
- B.
KNT
- C.
EHM
- D.
BEJ
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Correct answer: B
Concept — In an alphabet-based classification, every letter is replaced by its position in the English alphabet (A = 1, B = 2, ... , Z = 26). The ordered jumps between consecutive letters form that cluster's signature. Clusters sharing the same signature belong to one group, and the cluster whose signature differs is the odd one out.
Application — Convert each of the four clusters to positions and read off its jumps.
Cluster | Letter positions | Jumps |
|---|---|---|
NQV | 14, 17, 22 | +3, +5 |
KNT | 11, 14, 20 | +3, +6 |
EHM | 5, 8, 13 | +3, +5 |
BEJ | 2, 5, 10 | +3, +5 |
Cross-check — Three clusters carry the identical signature +3, +5, whereas K to N to T jumps +3 and then +6, one place more on the second jump. This also matches the note in the question: vowel count cannot decide the group, because NQV and KNT contain no vowel while EHM and BEJ contain one each, which splits the four into two pairs instead of isolating one cluster.
Answer — The cluster that does not share the common +3, +5 signature is KNT.