720p_5.15 Net 2013
Duration: 2 min
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The video presents a step-by-step solution to a number system conversion problem from a past GATE exam. The question asks to find the base 'x' of a number system where the decimal number (292)10 is equal to (1204)x. The instructor begins by writing the conversion equation: 292 = 1*x^3 + 2*x^2 + 0*x^1 + 4*x^0. He then simplifies this to the cubic equation x^3 + 2x^2 + 4 = 292, which further reduces to x^3 + 2x^2 - 288 = 0. The instructor then tests the given options: (A) 2, (B) 8, and (C) 10. He quickly eliminates option (A) by noting that the digit '2' is invalid in base 2. He eliminates (C) 10 by substituting it into the equation, which yields 1000 + 200 + 4 = 1204, a value much larger than 292. He then tests option (B) 8, which gives 512 + 128 + 4 = 644, also incorrect. Since none of the options work, he concludes the correct answer is (D) None of the above. The video is a clear demonstration of how to convert between number systems and solve for an unknown base using algebraic methods.
Chapters
0:00 – 1:47 00:00-01:47
The video starts with a question displayed on a whiteboard: 'Given that (292)10 = (1204)x in some number system x. The base x of that number system is (NET-DEC-2013)'. The options are (A) 2, (B) 8, (C) 10, and (D) None of the above. The instructor begins the solution by writing the conversion formula in red ink: (292)10 = 1*x^3 + 2*x^2 + 0*x^1 + 4*x^0. He simplifies this to 292 = x^3 + 2x^2 + 4. He then rearranges the equation to x^3 + 2x^2 - 288 = 0. He proceeds to test the options. For (A) 2, he notes that the digit '2' is not valid in base 2, so it's invalid. For (C) 10, he substitutes x=10 into the equation, getting 1000 + 200 + 4 = 1204, which is not 292. For (B) 8, he substitutes x=8, getting 512 + 128 + 4 = 644, which is also not 292. Since none of the options are correct, he concludes the answer is (D) None of the above. The instructor's name, Sanchit Jain Sir, and the channel name, Knowledge Gate Educator, are visible at the bottom of the screen.
The video demonstrates a systematic approach to solving a number system problem. The core concept is that a number in base x can be expanded into a polynomial of powers of x. The instructor correctly sets up the equation 292 = 1*x^3 + 2*x^2 + 0*x^1 + 4*x^0, which is the fundamental principle of positional number systems. The solution process involves algebraic manipulation to form a cubic equation and then testing the given multiple-choice options. A key insight is the rule that a digit in a number system must be less than the base, which allows for the immediate elimination of option (A) 2. The final step is a logical elimination process, showing that the correct answer is not among the choices, leading to the conclusion that (D) is the correct answer.