Four letter-cluster pairs have been given, out of which three are alike in…

Key idea: each letter in the second cluster is obtained by moving 5 positions forward in the alphabet from the corresponding letter in the first cluster (wrap around from Z to A).

• "FHJ – KMO": F→K (+5), H→M (+5), J→O (+5).

• "CEG – HJL": C→H (+5), E→J (+5), G→L (+5).

• "KMO – PRT": K→P (+5), M→R (+5), O→T (+5).

• "VXZ – ACF": V→A (+5 with wrap), X→C (+5 with wrap), Z→F

Check the numeric shifts for the last pair:

• V (22) → A (1): 22 + 5 = 27 → wrap to 1 (A), so +5.

• X (24) → C (3): 24 + 5 = 29 → wrap to 3 (C), so +5.

• Z (26) → F (6): 26 + 5 = 31 → wrap to 5 (E). To get F (6) would require +6, so this is not +5.

Conclusion: the pair "VXZ – ACF" is different because the last letter uses a +6 shift instead of the consistent +5 shift used in all other pairs.