This question is based on the five, three-digit numbers given below. (Left)…

In digit-position reasoning puzzles built on a set of numbers, the given numbers are first ranked by their overall numeric value to identify extremes such as the lowest and the highest number in the set. Each number is then read digit by digit strictly from left to right, so for any three-digit number the leftmost (hundreds-place) digit is its first digit, the middle (tens-place) digit is its second digit, and the rightmost (units-place) digit is its third digit — exactly the convention illustrated by the example given with the question.

1. List the five three-digit numbers given: 895, 915, 548, 584, 624.

2. Compare them by overall value: 548 < 584 < 624 < 895 < 915.

3. The lowest number in the set is 548 and the highest number in the set is 915.

4. Following the left-to-right convention, the second digit of 548 (its tens-place digit) is 4.

5. Following the same convention, the third digit of 915 (its units-place digit) is 5.

6. Add the two digits obtained: 4 + 5 = 9.

As an independent check on the ranking, compare only the hundreds-place digits first: 8, 9, 5, 5, 6. The smallest hundreds digit, 5, is shared by 548 and 584, so their tens digits (4 and 8) break the tie, confirming 548 as the overall lowest; the largest hundreds digit, 9, belongs uniquely to 915, confirming it as the overall highest. This matches the ranking used above, so the resultant 9 obtained is verified.