6 teachers P, Q, R, S, T and U have to present lectures. Each teacher will…
2021
6 teachers P, Q, R, S, T and U have to present lectures. Each teacher will present a lecture on one day from Monday to Saturday. Each teacher presents on a different day. There are 3 male and 3 female teachers. Each male is married to one of the females. More than 2 people present between T and U. R presents on Friday but his wife does not present on Monday. P presents on the next day of S. Two people present between P and U. P’s wife presents on the next day of P. Gender of T and U is the same. Which of the following statement is NOT correct?
- A.
Q is a female teacher and her husband presents on Wednesday
- B.
R and U are married couples
- C.
S’s wife presents on Monday
- D.
Two lectures are presented between Q and S
Attempted by 6 students.
Show answer & explanation
Correct answer: D
Step 1: Place the confirmed positions
R is on Friday(5). S, P, and P's wife must be consecutive. Placing them on Tuesday(2), Wednesday(3), and Thursday(4) is the only way to satisfy the condition "2 people between P and U", placing U on Saturday(6).
Step 2: Fill remaining days and identify T & Q
Since U is Saturday(6) and "more than 2 people are between T and U", T must be on Monday(1). This leaves Thursday(4) for Q (who is P's wife).
Step 3: Determine Genders (3 Male, 3 Female)
P and R are males. T and U share the same gender. To maintain a 3M/3F ratio, T and U must be females. Therefore, S is the last male. (Males: P, R, S | Females: Q, T, U).
Step 4: Determine Couples
P is married to Q. R's wife is not on Monday (T), so R must be married to U. This leaves S married to T.
Schedule: 1-T(F), 2-S(M), 3-P(M), 4-Q(F), 5-R(M), 6-U(F).
Step 5: Verify the Options
Checking statement D: S presents on Tuesday, Q presents on Thursday. There is only ONE lecture (P) between them. Statement D is incorrect.
Final Answer: Option D