This question is based on the following words: PIC, WRY, WAS, JOY. In each…
2026
This question is based on the following words: PIC, WRY, WAS, JOY. In each word, change every vowel to the second letter after it in the English alphabet and every consonant to the immediately preceding letter. In how many letter-clusters formed this way will no vowel appear?
Answer: B. Two — ConceptA vowel is one of A, E, I, O, and U. To apply a letter-change rule reliably, transform each character independently, write the complete new cluster,…
- A.
One
- B.
Two
- C.
Three
- D.
Four
Attempted by 33 students.
Show answer & explanation
Correct answer: B
Concept
A vowel is one of A, E, I, O, and U. To apply a letter-change rule reliably, transform each character independently, write the complete new cluster, and then test that cluster for vowels.
Application
Apply the two rules to each word: a vowel moves two letters forward, while a consonant moves one letter backward.
PIC becomes OKB: P becomes O, I becomes K, and C becomes B. The resulting cluster contains the vowel O.
WRY becomes VQX: W becomes V, R becomes Q, and Y becomes X. The resulting cluster contains no vowel.
WAS becomes VCR: W becomes V, A becomes C, and S becomes R. The resulting cluster contains no vowel.
JOY becomes IQX: J becomes I, O becomes Q, and Y becomes X. The resulting cluster contains the vowel I.
Cross-check
Only VQX and VCR contain none of A, E, I, O, or U. Therefore, the required count is two.