In a certain code language, ‘LEAP’ is coded as ‘9875’ and ‘LEAD’ is coded as…
2026
In a certain code language, ‘LEAP’ is coded as ‘9875’ and ‘LEAD’ is coded as ‘3897’. What is the code for ‘D’ in the given code language?
Answer: B. 3 — Concept: in this kind of letter-to-number coding the digits are not tied to the positions of the letters. A code is simply a jumbled collection of digits, one…
- A.
5
- B.
3
- C.
9
- D.
8
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Show answer & explanation
Correct answer: B
Concept: in this kind of letter-to-number coding the digits are not tied to the positions of the letters. A code is simply a jumbled collection of digits, one digit standing for each letter of the word. Two such words can therefore be compared as collections: a digit lying in both codes must stand for a letter lying in both words, while a digit lying in one code alone must stand for the letter that only that word carries.
Application: place the two given words next to their codes.
Word | Letters | Digits of its code |
|---|---|---|
LEAP | L, E, A, P | 9, 8, 7, 5 |
LEAD | L, E, A, D | 3, 8, 9, 7 |
Now work through the comparison step by step.
LEAP and LEAD begin with the same three letters L, E and A, and differ only in their last letter — P in LEAP and D in LEAD.
Write each code as a collection of digits: 9875 gives 5, 7, 8 and 9, while 3897 gives 3, 7, 8 and 9.
The digits lying in both collections are 7, 8 and 9 — three shared digits for exactly three shared letters, so 7, 8 and 9 stand for L, E and A in some order.
That leaves 5 in the code of LEAP, and P is the letter of LEAP still without a digit, so P = 5.
That leaves 3 in the code of LEAD, and D is the letter of LEAD still without a digit, so D = 3.
Cross-check: rebuild both codes from this assignment. L, E and A take 7, 8 and 9 in some order; adding P = 5 gives exactly the four digits of 9875, and adding D = 3 gives exactly the four digits of 3897. Both codes are reproduced, so the code for D is 3.
Contrast: reading the codes position by position does not work here. It would make L equal to 9 from LEAP and equal to 3 from LEAD at the same time, which is impossible, so the digits must be treated as a jumbled set rather than as a letter-by-letter list.