Match the pairs in List I with the pairs of analogies in List II. List I (A)…
2020
Match the pairs in List I with the pairs of analogies in List II.
List I
(A) Lizard : Reptile
(B) Tennis : Court
(C) Bull : Cow
(D) Botany : Plant
List II
(I) Skating : Rink
(II) Haematology : Blood
(III) Eagle : Bird
(IV) Wizard : Witch
Choose the correct answer from the options given below:
- A.
(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- B.
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- C.
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- D.
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Show answer & explanation
Correct answer: C
Concept
In an analogy-matching problem, the goal is to identify the precise logical relationship inside each given pair and then pair it with the item that shares the identical relationship. Two pairs match only when the connection between their two terms is of the same kind (for example member-to-class, male-to-female, sport-to-venue, or science-to-subject-studied).
Application
Identify the relationship in each List I pair and locate the List II pair built on the same relationship:
List I pair | Relationship | Matching List II pair |
|---|---|---|
Lizard : Reptile | a member belongs to its biological class | Eagle : Bird |
Tennis : Court | a sport played on its dedicated venue | Skating : Rink |
Bull : Cow | the male paired with the female of the same kind | Wizard : Witch |
Botany : Plant | a science paired with the subject it studies | Haematology : Blood |
Cross-check
Reading the matches together gives Lizard-Reptile with Eagle-Bird, Tennis-Court with Skating-Rink, Bull-Cow with Wizard-Witch, and Botany-Plant with Haematology-Blood, i.e. the mapping (A)-(III), (B)-(I), (C)-(IV), (D)-(II). Each List II item is used exactly once and every relationship type lines up, so the mapping is internally consistent.