The oxidation state of iron in Fe(CO)₅ is
2016
The oxidation state of iron in Fe(CO)₅ is
- A.
0
- B.
2
- C.
3
- D.
5
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Correct answer: A
In coordination and organometallic chemistry, carbon monoxide (CO) is treated as a neutral ligand by IUPAC convention — every CO group bonded to a metal carries a formal charge contribution of 0 toward the complex's overall charge. The oxidation state of the central metal in a complex is then found from the requirement that the metal's oxidation number plus the total charge contributed by all ligands must equal the complex's overall charge.
Fe(CO)₅ is a neutral, uncharged molecule, so its overall charge is 0.
It contains five CO ligands, and each one carries a formal charge contribution of 0, so together they contribute 5 × 0 = 0 to the total charge.
Let x be the oxidation number of the iron atom. The charge-balance equation is: x + 0 = 0.
Solving this equation gives x = 0.
This is confirmed independently by the compound's systematic IUPAC name, pentacarbonyliron(0), where the (0) states the metal's oxidation state directly. The same zero-oxidation-state pattern holds for other neutral homoleptic metal carbonyls, such as Ni(CO)₄ and Cr(CO)₆, reinforcing that CO's neutral-ligand convention is general, not specific to this one compound.
Hence, the oxidation state of iron in Fe(CO)₅ is 0.