Match List - 1 with List - II: List-1 List - II [Population mean(μ) and…
2025
Match List - 1 with List - II:
List-1 List - II
[Population mean(μ) and (1/N)Σxi²] [Population standard deviation (σ)]
A. μ=9, (1/N)Σxi²=117 I. 10
B. μ=10, (1/N)Σxi²=200 II. 4
C. μ=11, (1/N)Σxi²=202 III. 6
D. μ=12, (1/N)Σxi²=160 IV. 9
Choose the correct answer from the options given below:
- A.
A-III, B-IV, C-II, D-I
- B.
A-II, B-I, C-IV, D-III
- C.
A-III, B-I, C-IV, D-II
- D.
A-I, B-IV, C-II, D-III
Show answer & explanation
Correct answer: C
Concept: For population data, the standard deviation is obtained from the variance using σ² = (1/N)Σxi² − μ² — subtract the square of the population mean from the mean of the squares — and then σ = √(σ²).
A: μ = 9, (1/N)Σxi² = 117, so σ² = 117 − 81 = 36 and σ = 6, matching the List-II value III.
B: μ = 10, (1/N)Σxi² = 200, so σ² = 200 − 100 = 100 and σ = 10, matching the List-II value I.
C: μ = 11, (1/N)Σxi² = 202, so σ² = 202 − 121 = 81 and σ = 9, matching the List-II value IV.
D: μ = 12, (1/N)Σxi² = 160, so σ² = 160 − 144 = 16 and σ = 4, matching the List-II value II.
Cross-check: List-II assigns I = 10, II = 4, III = 6, IV = 9. Each computed σ above lands on exactly one of these four values with none repeated, so the pairing is internally consistent.
This gives A-III, B-I, C-IV, D-II, which is the pairing listed among the options.