Find the number that can replace Qmark (?) in the series given below. 7, 12,…

Key pattern: each term = previous term × position − consecutive even numbers (2, 4, 6, ...).

• Term 2: 7 × 2 − 2 = 14 − 2 = 12

• Term 3: 12 × 3 − 4 = 36 − 4 = 32

• Term 4: 32 × 4 − 6 = 128 − 6 = 122

• Term 5 (missing): 122 × 5 − 8 = 610 − 8 = 602

• Term 6: 602 × 6 − 10 = 3612 − 10 = 3602

• Term 7: 3602 × 7 − 12 = 25214 − 12 = 25202

Answer: 602