If 1² + 2² + ... + 9² = 285, then the value of (0.11)² + (0.22)² + ... +…
2018
If 1² + 2² + ... + 9² = 285, then the value of (0.11)² + (0.22)² + ... + (0.99)² is:
- A.
2.4485
- B.
0.24485
- C.
3.4485
- D.
0.34485
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Correct answer: C
The value of (0.11)² + (0.22)² + ... + (0.99)² is 3.4485.
This is derived by recognizing that each term is (0.11k)² for k from 1 to 9,
which simplifies to (0.01)² × 11² × (1² + 2² + ... + 9²) = 0.0001 × 121 × 285 = 3.4485.