The Octal equivalent of the binary number 1011101011 is :

Solution:

1. Pad the binary number with leading zeros so its length is a multiple of three: 1011101011 → 001 011 101 011.

2. Group the padded binary into threes from the left (these groups come from grouping the original number from the right): 001, 011, 101, 011.

3. Convert each 3-bit group to its octal digit: 001 = 1, 011 = 3, 101 = 5, 011 = 3.

4. Combine the digits to get the octal number: 1353.

Therefore, the octal equivalent of the binary number 1011101011 is 1353.